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Crash of a Tupolev TU-144D in Kladkovo: 2 killed

eureka math grade 4 lesson 36 homework 4.3

The Unique Burial of a Child of Early Scythian Time at the Cemetery of Saryg-Bulun (Tuva)

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Pages:  379-406

In 1988, the Tuvan Archaeological Expedition (led by M. E. Kilunovskaya and V. A. Semenov) discovered a unique burial of the early Iron Age at Saryg-Bulun in Central Tuva. There are two burial mounds of the Aldy-Bel culture dated by 7th century BC. Within the barrows, which adjoined one another, forming a figure-of-eight, there were discovered 7 burials, from which a representative collection of artifacts was recovered. Burial 5 was the most unique, it was found in a coffin made of a larch trunk, with a tightly closed lid. Due to the preservative properties of larch and lack of air access, the coffin contained a well-preserved mummy of a child with an accompanying set of grave goods. The interred individual retained the skin on his face and had a leather headdress painted with red pigment and a coat, sewn from jerboa fur. The coat was belted with a leather belt with bronze ornaments and buckles. Besides that, a leather quiver with arrows with the shafts decorated with painted ornaments, fully preserved battle pick and a bow were buried in the coffin. Unexpectedly, the full-genomic analysis, showed that the individual was female. This fact opens a new aspect in the study of the social history of the Scythian society and perhaps brings us back to the myth of the Amazons, discussed by Herodotus. Of course, this discovery is unique in its preservation for the Scythian culture of Tuva and requires careful study and conservation.

Keywords: Tuva, Early Iron Age, early Scythian period, Aldy-Bel culture, barrow, burial in the coffin, mummy, full genome sequencing, aDNA

Information about authors: Marina Kilunovskaya (Saint Petersburg, Russian Federation). Candidate of Historical Sciences. Institute for the History of Material Culture of the Russian Academy of Sciences. Dvortsovaya Emb., 18, Saint Petersburg, 191186, Russian Federation E-mail: [email protected] Vladimir Semenov (Saint Petersburg, Russian Federation). Candidate of Historical Sciences. Institute for the History of Material Culture of the Russian Academy of Sciences. Dvortsovaya Emb., 18, Saint Petersburg, 191186, Russian Federation E-mail: [email protected] Varvara Busova  (Moscow, Russian Federation).  (Saint Petersburg, Russian Federation). Institute for the History of Material Culture of the Russian Academy of Sciences.  Dvortsovaya Emb., 18, Saint Petersburg, 191186, Russian Federation E-mail:  [email protected] Kharis Mustafin  (Moscow, Russian Federation). Candidate of Technical Sciences. Moscow Institute of Physics and Technology.  Institutsky Lane, 9, Dolgoprudny, 141701, Moscow Oblast, Russian Federation E-mail:  [email protected] Irina Alborova  (Moscow, Russian Federation). Candidate of Biological Sciences. Moscow Institute of Physics and Technology.  Institutsky Lane, 9, Dolgoprudny, 141701, Moscow Oblast, Russian Federation E-mail:  [email protected] Alina Matzvai  (Moscow, Russian Federation). Moscow Institute of Physics and Technology.  Institutsky Lane, 9, Dolgoprudny, 141701, Moscow Oblast, Russian Federation E-mail:  [email protected]

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Eureka Math Grade 4 Module 3 Lesson 26 Answer Key

Engage ny eureka math 4th grade module 3 lesson 26 answer key, eureka math grade 4 module 3 lesson 26 problem set answer key.

Question 1. Draw place value disks to represent the following problems. Rewrite each in unit form and solve.

Eureka Math Grade 4 Module 3 Lesson 26 Problem Set Answer Key 1

Explanation: Drawn place value disks to represent the following problems. Rewrote each in unit form and solved as 6 ÷ 2 = 3, 6 ones ÷ 2 = 3 ones.

Eureka Math Grade 4 Module 3 Lesson 26 Answer Key-1

Explanation: Drawn place value disks to represent the following problems. Rewrote each in unit form and solved as 60 ÷ 2 = 30, 6 tens ÷ 2 = 3 tens.

Eureka Math Grade 4 Module 3 Lesson 26 Answer Key-2

Explanation: Drawn place value disks to represent the following problems. Rewrote each in unit form and solved as 600 ÷ 2 = 300, 6 hundred ÷ 2 = 3 hundred.

Eureka Math Grade 4 Module 3 Lesson 26 Answer Key-3

Explanation: Drawn place value disks to represent the following problems. Rewrote each in unit form and solved as 6,000 ÷ 2 = 3,000, 6 thousands ÷ 2 = 3 thousands.

Eureka Math Grade 4 Module 3 Lesson 26 Answer Key-4

Explanation: Drawn place value disks to represent each problem. Rewrote each in unit form and solved 12 ÷ 3 = 4, 12 ones ÷ 3 = 4 ones.

Eureka Math Grade 4 Module 3 Lesson 26 Answer Key-5

Explanation: Drawn place value disks to represent each problem. Rewrote each in unit form and solved 120 ÷ 3 = 40, 12 tens ÷ 3 = 4 tens.

Eureka Math Grade 4 Module 3 Lesson 26 Answer Key-6

Question 3. Solve for the quotient. Rewrite each in unit form. a. 800 ÷ 2 = 400 8 hundreds ÷ 2 = 4 hundreds Answer: 800 ÷ 2 = 400, 8 hundreds ÷ 2 = 4 hundreds,

b. 600 ÷ 2 = ____300____ Answer: Solved for the quotient, Rewrote each in unit form as 600 ÷ 2 = 300, 6 hundreds ÷ 2 = 3 hundreds,

c. 800 ÷ 4 = ___200_____ Answer: Solved for the quotient, Rewrote each in unit form as 800 ÷ 4 = 200, 8 hundreds ÷ 4 = 2 hundreds,

d. 900 ÷ 3 = __300_____ Answer: 900 ÷ 3 = 300, 9 hundreds ÷ 3 = 3 hundreds,

e. 300 ÷ 6 = ____50_____ 30 tens ÷ 6 = __5__ tens Answer: 300 ÷ 6 = 50, 30 tens ÷ 6 = 5 tens,

f. 240 ÷ 4 = ___60_____ Answer: 240 ÷ 4 = 60, 24 tens ÷ 4 = 6 tens,

g. 450 ÷ 5 = ___90_____ Answer: 450 ÷ 5 = 90, 45 tens ÷ 5 = 9 tens,

h. 200 ÷ 5 = ___40____ Answer: 200 ÷ 5 = 40, 20 tens ÷ 5 = 4 tens,

i. 3,600 ÷ 4 = ___900_____ 36 hundreds ÷ 4 = __9__ hundreds Answer: 3,600 ÷ 4 = 900, 36 hundreds ÷ 4 = 9 hundreds,

j. 2,400 ÷ 4 = ___600_____ Answer: 2,400 ÷ 4 = 600, 24 hundreds ÷ 4 = 6 hundreds,

k. 2,400 ÷ 3 = ____800___ Answer: 2,400 ÷ 3 = 800, 24 hundreds ÷ 3 = 8 hundreds,

l. 4,000 ÷ 5 = __800____ Answer: 4,000 ÷ 5 = 800, 40 hundreds ÷ 5 = 8 hundreds,

Question 4. Some sand weighs 2,800 kilograms. It is divided equally among 4 trucks. How many kilograms of sand are in each truck? Answer: 700 kilograms of sand are there in each truck,

Explanation: Given some sand weighs 2,800 kilograms. It is divided equally among 4 trucks. Number of kilograms of sand are there in each truck is 2,800 kilograms ÷ 4 = 700 kilograms. Therefore 700 kilograms of sand are there in each truck.

Question 5. Ivy has 5 times as many stickers as Adrian has. Ivy has 350 stickers. How many stickers does Adrian have? Answer: Adrian have 70 stickers,

Explanation: Given Ivy has 5 times as many stickers as Adrian has. Ivy has 350 stickers. Number of stickers does Adrian have are 350 stickers ÷ 5 = 70 stickers, therefore Adrian have 70 stickers.

Question 6. An ice cream stand sold $1,600 worth of ice cream on Saturday, which was 4 times the amount sold on Friday. How much money did the ice cream stand collect on Friday? Answer: On Friday the ice cream stand collected $400,

Explanation: Given an ice cream stand sold $1,600 worth of ice cream on Saturday, which was 4 times the amount sold on Friday. So money did the ice cream stand collected on Friday is $1,600 ÷ 4 = $400.

Eureka Math Grade 4 Module 3 Lesson 26 Exit Ticket Answer Key

Question 1. Solve for the quotient. Rewrite each in unit form. a. 600 ÷ 3 = 200 6 hundreds ÷ 3 = __2__ hundreds Answer: 600 ÷ 3 = 200, 6 hundreds ÷ 3 = 2 hundreds,

b. 1,200 ÷ 6 = ___200____ Answer: 1,200 ÷ 6 = 200, 12 hundreds ÷ 6 = 2 hundreds,

c. 2,100 ÷ 7 = __300_____ Answer: 2,100 ÷ 7 = 300, 21 hundreds ÷ 7 = 3 hundreds,

d. 3,200 ÷ 8 = _400____ Answer: 3,200 ÷ 8 = 400, 32 hundreds ÷ 8 = 4 hundreds,

Question 2. Hudson and 7 of his friends found a bag of pennies. There were 320 pennies, which they shared equally. How many pennies did each person get? Answer: Each person will get 40 pennies,

Explanation: Given Hudson and 7 of his friends found a bag of pennies. There were 320 pennies, which they shared equally. So number of pennies did each person will get is 320 pennies ÷ 8 = 40 pennies each.

Eureka Math Grade 4 Module 3 Lesson 26 Homework Answer Key

Eureka Math Grade 4 Module 3 Lesson 26 Homework Answer Key 2

Explanation: Drawn place value disks to represent the following problems. Rewrote each in unit form and solved as 6 ÷ 3 = 2, 6 ones ÷ 3 = 2 ones.

Eureka Math Grade 4 Module 3 Lesson 26 Answer Key-7

Explanation: Drawn place value disks to represent the following problems. Rewrote each in unit form and solved as 60 ÷ 3 = 20, 6 tens ÷ 3 = 2 tens.

Eureka Math Grade 4 Module 3 Lesson 26 Answer Key-8

Explanation: Drawn place value disks to represent each problem. Rewrote each in unit form and solved 600 ÷ 3 = 200, 6 hundreds ÷ 2 = 2 hundreds.

Eureka Math Grade 4 Module 3 Lesson 26 Answer Key-9

Explanation: Drawn place value disks to represent the following problems. Rewrote each in unit form and solved as 6,000 ÷ 3 = 2,000, 6 thousands ÷ 3 = 2 thousands.

Eureka Math Grade 4 Module 3 Lesson 26 Answer Key-10

Explanation: Drawn place value disks to represent each problem. Rewrote each in unit form and solved 12 ÷ 4 = 3, 12 ones ÷ 4 = 3 ones.

Eureka Math Grade 4 Module 3 Lesson 26 Answer Key-11

Explanation: Drawn place value disks to represent each problem. Rewrote each in unit form and solved 120 ÷ 4 = 30, 12 tens ÷ 4 = 3 tens.

Eureka Math Grade 4 Module 3 Lesson 26 Answer Key-12

Question 3. Solve for the quotient. Rewrite each in unit form. a. 800 ÷ 4 = 200 8 hundreds ÷ 4 = 2 hundreds Answer: 800 ÷ 4 = 200, 8 hundreds ÷ 4 = 2 hundreds,

Explanation: Solved for the quotient, Rewrote each in unit form as 800 ÷ 4 = 200, 8 hundreds ÷ 4 = 2 hundreds.

b. 900 ÷ 3 = ____300_____ Answer: 900 ÷ 3 = 300, 9 hundreds ÷ 3 = 3 hundreds,

c. 400 ÷ 2 = ___200_____ Answer: 400 ÷ 2 = 200, 4 hundreds ÷ 2 = 2 hundreds,

d. 300 ÷ 3 = __100___ Answer: 300 ÷ 3 = 100, 30 tens ÷ 3 = 10 tens,

e. 200 ÷ 4 = ___50______ 20 tens ÷ 4 = _5___ tens Answer: 200 ÷ 4 = 50, 20 tens ÷ 4 = 5 tens

f. 160 ÷ 2 = ____80_____ Answer: 160 ÷ 2 = 80, 16 tens ÷ 2 = 8 tens,

g. 400 ÷ 5 = __80______ Answer: 400 ÷ 5 = 80, 40 tens ÷ 5 = 8 tens,

Explanation: Solved for the quotient, Rewrote each in unit form as 400 ÷ 5 = 80, 40 tens ÷ 5 = 8 tens.

h. 300 ÷ 5 = ___60_____ Answer: 300 ÷ 5 = 60, 30 tens ÷ 5 = 6 tens

i. 1,200 ÷ 3 = ___400______ 12 hundreds ÷ 3 = _4___ hundreds Answer: 1,200 ÷ 3 = 400, 12 hundreds ÷ 3 = 4 hundreds,

j. 1,600 ÷ 4 = ___400_____ Answer: 1,600 ÷ 4 = 400, 16 hundreds ÷ 4 = 4 hundreds

k. 2,400 ÷ 4 = ___600____ Answer: 2,400 ÷ 4 = 600, 24 hundreds ÷ 4 = 6 hundreds

l. 3,000 ÷ 5 = __600____ Answer: 3,000 ÷ 5 = 600, 30 hundreds ÷ 5 = 6 hundreds

Question 4. A fleet of 5 fire engines carries a total of 20,000 liters of water. If each truck holds the same amount of water. how many liters of water does each truck carry? Answer: 4,000 liters of water each truck carry,

Explanation: Given a fleet of 5 fire engines carries a total of 20,000 liters of water. If each truck holds the same amount of water. The number of liters of water does each truck carry is 20,000 ÷ 5 = 4,000 liters.

Question 5. Jamie drank 4 times as much juice as Brodie. Jamie drank 280 milliliters of juice. How much juice did Brodie drink? Answer: 70 milliliters of juice Brodie drank,

Explanation: Given Jamie drank 4 times as much juice as Brodie. Jamie drank 280 milliliters of juice. So number of liters of juice did Brodie drank is 280 milliliters ÷ 4 = 70 milliliters.

Question 6. A diner sold $2,400 worth of French fries in June, which was 4 times as much as was sold in May. How many dollars’ worth of French fries were sold at the diner in May? Answer: $600 dollars’ worth of French fries were sold at the diner in May,

Explanation: Given a diner sold $2,400 worth of French fries in June, which was 4 times as much as was sold in May. So number of dollars’ worth of French fries were sold at the diner in May is $2,400 ÷ 4 = $600.

Eureka Math Grade 4 Module 3 Lesson 26 Template Answer Key

thousands hundreds tens

ones

 

 

 

 

 

 

 

_________1,000____________________________

Eureka Math Grade 4 Module 3 Lesson 26 Answer Key-13

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  5. Eureka Math Grade 4 Module 3 Lesson 36 Answer Key

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